The multiplication rule for dependent events is used since we are interested in the first player being a senior and the second player being a senior. The events are dependent since we are selecting the players without replacement. We are looking for:
Using Bayes’ Theorem
P(Train) = 0.65; implies P(No Train) = 1 – 0.65 = 0.35
P(Bus) = 0.18; implies P(No Bus) = 1 – 0.18 = 0.82
P(Train and Bus) = 0.06
Create a table from this information:
a. P(No Train) = 0.39
b. P(Neither Train Nor Bus) = 0.11
c. P(Train Bus 0.06/0.24 0.25
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